Factorize: x^6 - 10x^3 + 27:(^-raised to)

Dear Ajinkya

x⁶ - 10x3 + 27=0

let x³ =t

so t² -10t +27 =0

discriminant =(-10)^2-4(1)(27)  =-8 which is less than 0.

So,discriminant of this equation is negative so  no real value of t.

So complex roots exist for this equation,which are {10+i(8)^(1/2)}/2 and {10-i(8)^(1/2)}/2.

So this equation has no real value of x.

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